1.5 hour, Total Marks: 200 (80 MCQ+ 120 Tech)
1. Fill in the blanks
(a) If angle of friction is 30°, Passive Earsh pressure coefficient ______.
(b) _______ tube is used for pressure, velocity & elevation head.
(c) If 100% aggregate retained in #100 then FM ______
(d)
2. A uniform diameter pipe pressure at A & B point are 168 kpa & 300 kpa. Point A is 10 m upward. Find the flow direction.
3. A constant diameter pipes' value of piezometric head and pitot tube head are 30cm and 40cm. Find out the velocity.
4. Normal depth determination of a wide channel. (All data given)
5. Critical depth calculation of wide channel. (All data given)
6. List of diversion head work components.
7. FM calculation with % of silt and clay and Coefficient of uniformity
8. Water content of a saturated soil is 20%. Calculate void ratio (e), porosity (n) and saturated unit weight (ɣ(sat)).
9. Measured area is 100 m², Chain length is 25m and actual chain length is 25.01 m. Find the actual area.
10. fc = 3 ksi, fy = 60 ksi. Find Minimum and Maximum Reinforcement Ratio.
11. SFD, BMD
12. Spot speed data were collected at a section of highway during and utility maintenance work. The speed characteristics are given below. Determine whether there was any significant difference between the average speed at the 95% cofidence level.
Given, Before Improvement, 1; After Improvement, 2;
u₁ = 35.5 mph; S1=7.5 mph; n1= 250
U2=38.7 mph; S2=7.4 mph; n2 = 280
13. A signalized intersection approach has three lanes with no exclusive left or right turning lanes. The approach has a 40-second green out of a 75-second cycle. The yellow plus all-red intervals for phase total 4.0 seconds. If the start-up lost time is 2.3s/phase, the clearance lost time is 1.1s/phase, and thesaturation headway is 2.48 s/veh under prevailing conditions, what is the capacity of the intersection approach?
Ans:
Calculate the saturation flow rate by using the following equation
S = 3600/h, where h is the saturation headway
S = 3600/2.48 = 1452 veh/hg
Calculate the effective green time
G(i) = G(i) + Y(i) – t(Li), where G(i) is the actual green time for movement, Y(i) is the sum of yellow and all red intervals for movement, and t(Li), is the total lost time for movement
G(i) = 40, Y(i) = 4, t(Li) = 2.3 + 1.1 = 3.4
G(i) = 40 + 4 – 3.4 = 40.6
Calculate the capacity of an intersection approach by using the following equation
C(i) = s(i) [g(i)/C], where s(i) the saturation flow rate, g(i) is the effective green time, and C is the cycle length
s(i) = 1452, g(i) = 40.6, C = 75
C(i) = 1452 x (40.6/75) = 786.01 veh/h/ln
The capacity of intersection approach is 786.01
14. For 5 MLD (million litre per day) water, 20% CL2 is presented in bleching powder. Find Cl amount in kg.
15. Peak value of 6h flood hydrograph is 35 m³/s. Constant base flow 10 m3/s. Effictive reainfall depth is 5 cm. Determine 6h Unit hydrograph.
16. Coal amount is 2000 kg. Sulpher emission is 3% of coal per second. Determine SO₂ emission in million kg/year.
17. Simple Math
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